11p^2-110p=0

Solution for 11p^2-110p=0 equation:

11p^2-110p=0

a = 11; b = -110; c = 0;
Δ = b2-4ac
Δ = -1102-4·11·0
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-110}{2*11}=\frac{0}{22}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+110}{2*11}=\frac{220}{22}
=10
$